![]() ![]() It is an f –block element as the last electron occupies the f–orbital. (iii) Since n = 6, the element is present in the 6 th period. Hence, the element is Titanium ( 183d 24s 2. Therefore, it is a 4 th period and 4 th group element. = Number of s–block groups (4s 2) + number of d–block groups (3d 2) Thus, the corresponding group of the element It is a d–block element as d–orbitals are incompletely filled. (ii) Since n = 4, the element belongs to the 4 th period. Hence, the element is Sulphur ( 103s 23p 4) Therefore, the element belongs to the 3 rd period and 16 th group of the periodic table. = Number of s–block groups (3s 2) + number of d–block groups ( 10 + number of p–electrons(3p 4) There are four electrons in the p–orbital. It is a p–block element since the last electron occupies the p–orbital. (i) Since n = 3, the element belongs to the 3 rd period. ![]()
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